Question:medium

The value of integral $\int_{0}^{1}\int_{x}^{1}\frac{1}{1+y^{2}}\cdot dydx$ is equal to

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In double integrals, if the inner integral seems "unfriendly," check if changing the order produces a $y dy$ or $x dx$ term. This often allows for a simple logarithmic substitution.
Updated On: Jun 6, 2026
  • $1-\ln(2)$
  • $\frac{1}{2}\ln(2)$
  • $\frac{\pi}{4}$
  • $\frac{\pi}{2}-\ln 2$
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The Correct Option is B

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