Question:medium

The value of $\int \frac{x^2-1}{(x^4+3x^2+1)\tan^{-1}(x+\frac{1}{x})} dx$ is:

Show Hint

When you see $x^2 \pm 1$ in the numerator and $x^4 + kx^2 + 1$ in the denominator, look for substitutions involving $(x \pm 1/x)$.
Updated On: May 16, 2026
  • $\ln|\tan^{-1}(x+1/x)| + C$
  • $\tan^{-1}(x+1/x) + C$
  • $\frac{1}{2} (\tan^{-1}(x+1/x))^2 + C$
  • $\ln|x^4+3x^2+1| + C$
Show Solution

The Correct Option is A

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