The value of $\int_{0}^{\pi}\frac{\sin x}{1+\sin x}dx$ is equal to}
\textit{Note: The upper limit in the integral from the original paper contains a typo ($x$ instead of $\pi$). It has been corrected here to yield the valid options provided.
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Logic Tip: The integral $\int \frac{1}{1 \pm \sin x} dx$ is incredibly common. Memorize that multiplying by the conjugate always turns it into $\sec^2 x \mp \sec x \tan x$, which integrates immediately to $\tan x \mp \sec x$.