The standard Gaussian integral $\int_{-\infty}^{\infty} e^{-x^2} dx = \sqrt{\pi}$ is extremely useful.
By symmetry, over the interval $[0, \infty)$, it is $\frac{\sqrt{\pi}}{2}$.
The product of two such independent integrals is $(\frac{\sqrt{\pi}}{2})^2 = \frac{\pi}{4}$.