Question:medium
The value of \(\displaystyle \int_{0}^{2\pi} \frac{\sin 2x}{x(2\pi - x)}\,dx\) is equal to:
The value of \(\displaystyle \int_{0}^{2\pi} \frac{\sin 2x}{x(2\pi - x)}\,dx\) is equal to:
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For integrals on symmetric intervals or using the property \(\int_0^{2a} f(x) dx\), check if the function satisfies \(f(2a-x) = -f(x)\). If it does, the integral over that range is always zero.
Updated On: Jun 25, 2026
- \(\pi\)
- \(\frac{\pi}{2}\)
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{8}\)
- 0
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The Correct Option is
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