Question:medium
The value of \(\displaystyle \int_{0}^{1} \frac{t}{(t+1)^3}\,dt\) is equal to:
The value of \(\displaystyle \int_{0}^{1} \frac{t}{(t+1)^3}\,dt\) is equal to:
Show Hint
Manipulating the numerator to look like the denominator (\(t+1-1\)) is almost always faster than using substitution in rational integrals.
Updated On: Jun 25, 2026
- \(\frac{1}{8}\)
- \(\frac{3}{8}\)
- \(\frac{5}{8}\)
- \(\frac{7}{8}\)
- \(\frac{1}{4}\)
Show Solution
The Correct Option is A
Solution and Explanation
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