Question

The value of \(i^i\), (\(i^2 = -1\)) is

• A. 0
• B. 1
• C. -1
• D. \(e^{-\pi/2}\)

Hint:

It is a surprising mathematical fact that an imaginary number raised to an imaginary power (\( i^i \)) results in a purely real number:
\[ i^i = e^{-\pi/2} \approx 0.2079 \]

Answer 1

The Correct Option is D