Question:medium

The value of \[ \frac34+\frac{15}{16}+\frac{63}{64}+\cdots \text{ up to } n \text{ terms is} \]

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Rewrite series into simple standard sums.

Updated On: Mar 23, 2026

\(n-\dfrac{4^n}{3}-\dfrac13\)
\(n+\dfrac{4^n}{3}-\dfrac13\)
\(n+\dfrac{4^n}{3}-\dfrac13\)
\(n-\dfrac{4^n}{3}+\dfrac13\)

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The Correct Option is D

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