Question:medium

The value of \( {}^{47}C_4 + \sum_{j=1}^5 {}^{(52-j)C_3 \) is

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Always start combining terms with the smallest index using the Pascal's identity: ${}^nC_r + {}^nC_{r-1} = {}^{n+1}C_r$.
Updated On: May 12, 2026
  • \( {}^{52}C_4 \)
  • \( {}^{52}C_2 \)
  • \( {}^{48}C_4 \)
  • \( {}^{48}C_2 \)
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The Correct Option is A

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