Given an atmospheric pressure of \( 1 \, \text{bar} \) and a vacuum pressure of \( 50 \, \text{mm of Hg} \), the absolute pressure is calculated as:
Absolute pressure = Atmospheric pressure – Vacuum pressure
\( = 1 \, \text{bar} - \frac{50 \, \text{mm of Hg}}{760 \, \text{mm of Hg}} \times 1 \, \text{bar} = 0.92 \, \text{bar}. \)
A wooden cubical block of relative density 0.4 is floating in water. Side of cubical block is $10 \text{ cm}$. When a coin is placed on the block, it dips by $0.3 \text{ cm}$, weight of coin is: