Question:medium

The two population ratio of Snyders used to test equilibrium for dominant genes are which of the following?

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Snyder’s test applies to dominant gene equilibrium; always check ratios involving $(1+q)$ in the denominator.
Updated On: Feb 20, 2026
  • $\dfrac{q^{2}}{(1+q)^{2}}$ and $\dfrac{q}{(1+q)}$
  • $\dfrac{q^{2}}{(1-q)^{2}}$ and $\dfrac{q}{(1+q)}$
  • $\dfrac{q^{2}}{(1+q)^{2}}$ and $\dfrac{q}{(1+q)^{2}}$
  • $\dfrac{q^{2}}{(1-q)^{2}}$ and $\dfrac{q}{(1+q)^{2}}$
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Review Snyder’s test.
Snyder’s ratio is a population genetics tool for assessing equilibrium of dominant and recessive gene frequencies.
Step 2: Define the ratios.
This method compares expected genotype ratios utilizing allele frequency $q$. The derived ratios are: $\dfrac{q^{2}}{(1+q)^{2}}$ and $\dfrac{q}{(1+q)}$.
Step 3: Discard incorrect options.
Options (2), (3), and (4) present erroneous denominators or exponents, rendering them unsuitable for Snyder’s test.
Step 4: Final determination.
Consequently, the correct population ratios are $\dfrac{q^{2}}{(1+q)^{2}}$ and $\dfrac{q}{(1+q)}$.
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