Given the position vector \(\vec{r} = x\hat{i} + y\hat{j}\), where:
x = A cos ωt
y = 2A cos ωt
This indicates simple harmonic motion along both the x and y axes.
From these equations, we derive:
$\frac{x}{A}$ = cos ωt
$\frac{y}{2A}$ = cos ωt
Equating these gives: $\frac{x}{A} = \frac{y}{2A}$
Which simplifies to: y = 2x
This equation represents a straight line, thus ruling out parabolic or elliptical paths.
The motion is periodic and simple harmonic, occurring along the line defined by y = 2x.
A particle is subjected to simple harmonic motions as: $ x_1 = \sqrt{7} \sin 5t \, \text{cm} $ $ x_2 = 2 \sqrt{7} \sin \left( 5t + \frac{\pi}{3} \right) \, \text{cm} $ where $ x $ is displacement and $ t $ is time in seconds. The maximum acceleration of the particle is $ x \times 10^{-2} \, \text{m/s}^2 $. The value of $ x $ is: