Question:medium

The total power in the two side-frequencies of the resulting AM is one third of the total power in the modulated wave when the modulation index is

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For AM: \[ P_s=P_c\frac{m^2}{2} \] \[ P_t=P_c\left(1+\frac{m^2}{2}\right) \] At \(m=1\), sideband power becomes one-third of total transmitted power.

Updated On: Jun 25, 2026

\(25%\)
\(33%\)
\(>100%\)
\(66%\)

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The Correct Option is C

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