Question:medium

The total number of 7 digit positive integral numbers with distinct digits that can be formed using the digits 4, 3, 7, 2, 1, 0, 5 is:

Show Hint

When 0 is included in your set of digits and you need to form an \( n \)-digit number using all \( n \) digits, the formula is always \( (n-1) \times (n-1)! \). Here, \( (7-1) \times 6! = 6 \times 720 = 4320 \).
Updated On: May 2, 2026
  • \( 4320 \)
  • \( 4340 \)
  • \( 4310 \)
  • \( 4230 \)
  • \( 4220 \)
Show Solution

The Correct Option is A

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