The total number of 7 digit positive integral numbers with distinct digits that can be formed using the digits 4, 3, 7, 2, 1, 0, 5 is:
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When 0 is included in your set of digits and you need to form an \( n \)-digit number using all \( n \) digits, the formula is always \( (n-1) \times (n-1)! \). Here, \( (7-1) \times 6! = 6 \times 720 = 4320 \).