Question:medium

The time period of revolution of a charge \(q_1\) and of mass \(m\) moving in a circular path of radius \(r\) due to Coulomb force of attraction with another charge \(q_2\) at its centre is

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This derivation is identical to Kepler's Third Law for planets, where \(T^2 \propto r^3\). The constant of proportionality here simply uses electrical units instead of gravitational ones!
Updated On: May 6, 2026
  • \(\sqrt{\frac{16\pi^3 \epsilon_0 mr^3}{q_1 q_2}}\)
  • \(\sqrt{\frac{8\pi^2 \epsilon_0 mr^3}{q_1 q_2}}\)
  • \(\sqrt{\frac{\epsilon_0 mr^3}{16\pi q_1 q_2}}\)
  • \(\sqrt{\frac{16\pi^3 \epsilon_0 mr^3}{q_1 q_2}}\)
  • \(\sqrt{\frac{\pi^2 \epsilon_0 mr^3}{8q_1 q_2}}\)
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The Correct Option is D

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