To determine the new time period when the spring is cut into four equal parts, we need to understand the relationship between the spring constant and the time period of oscillation.
The time period T of a mass-spring system is given by the formula:
T = 2\pi \sqrt{\frac{m}{k}}
where:
When a spring of original length L is cut into four equal parts, the length of each part becomes \frac{L}{4}. The spring constant is inversely proportional to the length of the spring, which means for each smaller spring:
k_{\text{new}} = 4k
Now, suspending the same mass m to one of these smaller springs, the time period T_{\text{new}} can be calculated using:
T_{\text{new}} = 2\pi \sqrt{\frac{m}{k_{\text{new}}}}
Substituting k_{\text{new}} = 4k, we get:
T_{\text{new}} = 2\pi \sqrt{\frac{m}{4k}} = 2\pi \sqrt{\frac{1}{4} \cdot \frac{m}{k}} = \frac{1}{2} \cdot 2\pi \sqrt{\frac{m}{k}} = \frac{T}{2}
Thus, the new time period when the same mass is suspended from one part of the cut spring is \frac{T}{2}.
Therefore, the correct answer is T/2.