Question:medium
The time period of a simple pendulum of length \( \sqrt{5} \) m suspended in a car moving with uniform acceleration of \( 5 \, \text{m s}^{-2} \) in a horizontal straight road is (\( g = 10 \, \text{m s}^{-2} \))
The time period of a simple pendulum of length \( \sqrt{5} \) m suspended in a car moving with uniform acceleration of \( 5 \, \text{m s}^{-2} \) in a horizontal straight road is (\( g = 10 \, \text{m s}^{-2} \))
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In accelerating frames, always replace $g$ with $g_{\text{eff}} = \sqrt{g^2 + a^2}$.
Updated On: May 2, 2026
- $\frac{2\pi}{\sqrt{5}}$ s
- $\frac{\pi}{\sqrt{5}}$ s
- $5\pi$ s
- $4\pi$ s
- $3\pi$ s
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The Correct Option is A
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