Question:medium

The time period of a simple pendulum is $T$ in air. When the bob is completely immersed in a non-viscous liquid of density $\rho / 10$ (where $\rho$ is the density of the bob), the new time period of oscillation is: [H] [width=0.5\linewidth]{86.png}

Show Hint

Upthrust always opposes gravity, meaning $g_{\text{eff}}$ decreases and the pendulum swings slower (time period $T$ increases). This immediately eliminates options where the factor is less than 1.

Updated On: May 31, 2026

$T \sqrt{\frac{10}{9}}$
$T \sqrt{\frac{9}{10}}$
$T \sqrt{\frac{10}{11}}$
$T \sqrt{\frac{11}{10}}$

Show Solution

The Correct Option is A

Solution and Explanation

Was this answer helpful?

Questions Asked in AP EAPCET exam

Let \[ f(x)=\int \frac{\sqrt{x}}{(1+x)^2}\,dx \quad (x\geq 0) \] Then \[ f(3)-f(1) \] is equal to:

AP EAPCET - 2026
Definite and indefinite integrals

View Solution

Gas is being pumped into a spherical balloon at the rate of $ 30 \, \text{ft}^3/\text{min} $. Then the rate at which the radius increases when it reaches the value $ 15 \, \text{ft} $ is:

AP EAPCET - 2026
Differentiation

View Solution

Let the function $ f(x) $ be defined as $ f(x) = \frac{x - |x|}{x} $, then:

AP EAPCET - 2026
Definite and indefinite integrals

View Solution

If the direction ratios of two lines are given by $ l + m + n = 0 $ and $ mn - 2ln + lm = 0 $, then the angle between the lines is:

AP EAPCET - 2026
3D Geometry

View Solution

The time period of a simple pendulum is $T$ in air. When the bob is completely immersed in a non-viscous liquid of density $\rho / 10$ (where $\rho$ is the density of the bob), the new time period of oscillation is: [H] [width=0.5\linewidth]{86.png}

Show Hint

The Correct Option is A

Solution and Explanation

Top Questions on Pendulums

Questions Asked in AP EAPCET exam