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The time period of a particle executing simple harmonic motion is $2\pi$ second. If the maximum acceleration of the particle is $10 ms^{-2}$, then the maximum velocity of the particle is
The time period of a particle executing simple harmonic motion is $2\pi$ second. If the maximum acceleration of the particle is $10 ms^{-2}$, then the maximum velocity of the particle is
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Remember the relationship: $a_{max} = \omega \cdot v_{max}$. This allows you to switch between maximum acceleration and velocity without finding the amplitude explicitly.
Updated On: Mar 31, 2026
- $10 ms^{-1}$
- $20 ms^{-1}$
- $5 ms^{-1}$
- $15 ms^{-1}$
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The Correct Option is A
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