The Thiessen polygon method is used to calculate the average rainfall ($P$):
\[P = W_A \cdot P_A + W_B \cdot P_B + W_C \cdot P_C + W_D \cdot P_D\]
Here,
$W_A, W_B, W_C, W_D$ represent the Thiessen weights for gauges,
and $P_A, P_B, P_C, P_D$ are the rainfall values at gauges A, B, C, and D.
Using the provided data:
\[5 = 0.15 \cdot P_A + 0.25 \cdot 5 + 0.30 \cdot 4 + 0.30 \cdot 5\]
Simplifying this equation:
\[5 = 0.15 \cdot P_A + 1.25 + 1.2 + 1.5\]
\[5 = 0.15 \cdot P_A + 3.95\]
Solving for $P_A$:
\[0.15 \cdot P_A = 5 - 3.95 = 1.05\]
\[P_A = \frac{1.05}{0.15} = 7 \, \text{cm}\]
Therefore, the rainfall at gauge A is $7 \, \text{cm}$.