Rather than assuming the rope must travel the full ice thickness, remember that floating ice always has a "freeboard" — a portion above the waterline — governed by how its density compares to water's. The rope's minimum length is exactly that freeboard portion.
Since the rope only has to span the above-water freeboard of the floating ice rather than its full thickness, and that freeboard works out to 9 m for this problem, that is the minimum length required.
Therefore, the correct answer is 9 m.
A pitot tube connected to a U-tube mercury manometer measures the speed of air flowing in the wind tunnel as shown in the figure below. The density of air is 1.23 kg m\(^{-3}\) while the density of water is 1000 kg m\(^{-3}\). For the manometer reading of \( h = 30 \) mm of mercury, the speed of air in the wind tunnel is _________ m s\(^{-1}\) (rounded off to 1 decimal place). 
Consider a velocity field \( \vec{V} = 3z \hat{i} + 0 \hat{j} + Cx \hat{k} \), where \( C \) is a constant. If the flow is irrotational, the value of \( C \) is (rounded off to 1 decimal place).