The temperature of inversion of a thermocouple is 620°C and the neutral temperature is 300°C.what is the temperature of cold junction?

Question

A 200 g sample of water at 80°C is mixed with 100 g of water at 20°C. Assuming no heat loss to the surroundings, what is the final temperature of the mixture?

Answer 1

To solve this problem, we need to understand the relationship between the temperature of inversion, the neutral temperature, and the temperature of the cold junction in a thermocouple. These temperatures are related by the formula:

T_i = 2T_n - T_c

where:

T_i is the temperature of inversion.
T_n is the neutral temperature.
T_c is the temperature of the cold junction.

We are given:

T_i = 620^\circ C
T_n = 300^\circ C

We need to find the temperature of the cold junction, T_c.

Substituting the given values into the formula:

620 = 2 \times 300 - T_c

Simplifying the equation:

620 = 600 - T_c

Rearranging to find T_c:

T_c = 600 - 620 = -20^\circ C

Therefore, the temperature of the cold junction is -20^\circ C.

Thus, the correct answer is:

-20°C

Answer 2