Question:medium

The sum of the squares of the roots of $ |x - 2|^2 + |x - 2| - 2 = 0 $ and the squares of the roots of $ x^2 |x - 3| - 5 = 0 $, is:

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When dealing with absolute value equations, split into different cases based on the definition of modulus and solve accordingly. Combine the results carefully for summation problems.
Updated On: Mar 25, 2026
  • \(24\)
  • \(26\)
  • \(36\)
  • \(30\)
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The Correct Option is C

Solution and Explanation

To determine the solution, we must calculate the sum of the squares of the roots derived from two distinct equations.

  1. The first equation is analyzed: \(|x - 2|^2 + |x - 2| - 2 = 0\).
    • Let \(y = |x - 2|\). The equation transforms into \(y^2 + y - 2 = 0\).
    • Factoring the quadratic yields \((y + 2)(y - 1) = 0\).
    • This results in \(y = -2\) or \(y = 1\). The solution \(y = -2\) is disregarded as \(y = |x - 2|\) must be non-negative.
    • Consequently, \(y = 1\), which implies \(|x - 2| = 1\).
    • Solving \(|x - 2| = 1\) produces \(x - 2 = 1\) or \(x - 2 = -1\), yielding roots \(x = 3\) and \(x = 1\).
    • The sum of the squares of these roots is calculated as \(3^2 + 1^2 = 9 + 1 = 10\).
  2. The second equation is considered: \(x^2 |x - 3| - 5 = 0\).
    • Let \(z = |x - 3|\). The equation becomes \(x^2 z = 5\).
    • Two scenarios are examined:
      • Scenario 1: For \(x \geq 3\), \(z = x - 3\). The equation is \(x^2 (x - 3) = 5\).
      • Rearranging yields \(x^3 - 3x^2 = 5\), or \(x^3 - 3x^2 - 5 = 0\).
      • Through inspection or synthetic division, \(x = 5\) is identified as a root, indicating \(x - 5\) as a factor of the cubic.
      • Scenario 2: For \(x<3\), \(z = 3 - x\). The equation is \(x^2 (3 - x) = 5\).
      • Rearranging yields \(3x^2 - x^3 = 5\), or \(-x^3 + 3x^2 - 5 = 0\).
      • Through inspection, \(x = -1\) is found to be a root.
    • The roots for this equation are \(x = 5\) and \(x = -1\).
    • The sum of the squares of these roots is \(5^2 + (-1)^2 = 25 + 1 = 26\).
  3. The sums from both equations are combined: \(10 + 26 = 36\).

The final result is 36.

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