The sum of ages of 5 children born at intervals of 3 years each is 50 years. What is the age of the youngest child?
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In an arithmetic progression with an odd number of terms, the middle term is the average. Here, $50 / 5 = 10$ is the age of the 3rd child. Subtract $3 \times 2$ to find the youngest: $10 - 6 = 4$.