The straight line $\vec{r} = (\hat{i} + \hat{j} + 2\hat{k}) + t(2\hat{i} + 5\hat{j} + 3\hat{k})$ is parallel to the plane $\vec{r} \cdot (2\hat{i} + \hat{j} - 3\hat{k}) = 5$. Then the distance between the straight line and the plane is:
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Verify parallelism first by checking $\vec{b} \cdot \vec{n} = 0$. Here, $(2, 5, 3) \cdot (2, 1, -3) = 4 + 5 - 9 = 0$. This confirms the line is parallel and the distance is constant.