Step 1: Understand the line equation.
The line is given in symmetric form:
\[\n\frac{x-3}{3} = \frac{y-2}{1} = \frac{z-1}{0}\n\]
Since the denominator for \( z \) is \( 0 \), \( z \) is constant.
From:
\[\n\frac{z-1}{0} = k\n\quad \Rightarrow \quad\nz-1 = 0k\n\quad \Rightarrow \quad\nz=1\n\]
Therefore, \( z=1 \) for all points on the line.
Step 2: Analyze the direction.
Since \( z \) is constant, the line lies in the plane \( z=1 \).
The direction ratios are:
\[\n(3, 1, 0)\n\]
This means the line moves in \( x \) and \( y \) but not in \( z \).
Thus, the line is parallel to the x-y plane and perpendicular to the z-axis.
Step 3: Conclude the answer.
Hence, the line is perpendicular to the z-axis.