Note: The provided source material indicates that this question was cancelled. However, we can solve it as follows.
Step 1: Understanding the Concept:
The problem requires finding the equation of a line given a point it passes through and a line it is perpendicular to. This involves finding the slope from the given line and using the condition for perpendicular lines.
Step 2: Key Formula or Approach:
1. Find the slope of the given line \(11x - 7y = 13\). Let this be \(m_1\). The slope of a line \(Ax + By + C = 0\) is \(-A/B\).
2. The slope of a line perpendicular to it, \(m_2\), is given by \(m_2 = -1/m_1\).
3. Use the point-slope form of a line, \(y - y_1 = m_2(x - x_1)\), to find the equation of the required line.
4. Convert the equation to the form \(ax + by + c = 0\) and identify the value of `c`.
Step 3: Detailed Explanation:
1. Find the slope of the given line.
The line is \(11x - 7y = 13\).
Its slope is \(m_1 = -\frac{\text{coefficient of x}}{\text{coefficient of y}} = -\frac{11}{-7} = \frac{11}{7}\).
2. Find the slope of the perpendicular line.
The slope of our required line, \(m_2\), is the negative reciprocal of \(m_1\).
\[ m_2 = -\frac{1}{m_1} = -\frac{1}{11/7} = -\frac{7}{11} \]
3. Find the equation of the required line.
The line passes through the point \((x_1, y_1) = (-10, 7)\) and has a slope \(m_2 = -7/11\). Using the point-slope form:
\[ y - 7 = -\frac{7}{11}(x - (-10)) \]
\[ y - 7 = -\frac{7}{11}(x + 10) \]
Multiply both sides by 11 to eliminate the fraction:
\[ 11(y - 7) = -7(x + 10) \]
\[ 11y - 77 = -7x - 70 \]
Rearrange the equation into the form \(ax + by + c = 0\):
\[ 7x + 11y - 77 + 70 = 0 \]
\[ 7x + 11y - 7 = 0 \]
4. Identify the value of c.
Comparing this equation with \(ax + by + c = 0\), we see that \(c = -7\).
Step 4: Final Answer:
The calculated value of c is -7.