Question:medium

The steady-state error of Type-2 system for a standard unit velocity input is

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Keep this reference table in mind for steady-state errors ($e_{ss}$): {|c|c|c|c|} System Type & Step Input (Position) & Ramp Input (Velocity) & Parabolic Input (Accel.)
Type 0 & $\frac{1}{1+K_p}$ & $\infty$ & $\infty$
Type 1 & 0 & $\frac{1}{K_v}$ & $\infty$
Type 2 & 0 & 0 & $\frac{1}{K_a}$

Updated On: Jun 25, 2026

\(\frac{1}{1+K_v}\)
\(\infty\)
\(\frac{1}{K_v}\)
\(0\)

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The Correct Option is D

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