Question:medium

The standard sutureless cataract surgery done with phacoemulsification and a foldable IOL has an incision of:

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A foldable IOL lets phaco use a small, self sealing corneal wound, about 2 to 2.5 mm.
Updated On: Jul 8, 2026
  • 1 mm - 1.5 mm
  • 2 mm - 2.5 mm
  • 3 mm - 3.5 mm
  • 3.5 mm - 4 mm
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The Correct Option is B

Solution and Explanation

This question checks the incision size used in modern sutureless cataract surgery done with phacoemulsification and a foldable lens.

  1. 1 mm - 1.5 mm: Too small for the standard phaco probe and sleeve to pass through safely; this range belongs to special micro incision techniques, not the routine procedure.
  2. 2 mm - 2.5 mm: Wide enough for the phaco tip and sleeve, yet narrow enough that the corneal wound seals itself once a foldable lens is injected through it. This is the standard size.
  3. 3 mm - 3.5 mm: Larger than needed once foldable lenses came into use; this size fit older rigid lenses better and adds more astigmatism.
  4. 3.5 mm - 4 mm: Even larger, closer to an old style extracapsular cataract wound, and not needed for a foldable lens.

A wound of about 2 mm to 2.5 mm gives enough room for the instruments while staying small enough to self seal, which is why it is the standard for sutureless phacoemulsification with a foldable IOL.

Let's summarize:

  • Foldable IOLs pass through a small injector opening, so the wound does not need to match the lens's unfolded size.
  • A 2 mm to 2.5 mm clear corneal wound is the standard sutureless size used today.

So the correct incision range is 2 mm to 2.5 mm.

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