Question

The standard electrode potential for the half-cell reactions are $Zn^{2+} + 2e^{-} \rightarrow Zn;\ E^{\circ} = -0.76~V$ and $Fe^{2+} + 2e^{-} \rightarrow Fe;\ E^{\circ} = -0.44~V$. The emf of the cell reaction $Fe^{2+} + Zn \rightarrow Zn^{2+} + Fe$ is

• A. -0.32 V
• B. -1.20 V
• C. +1.20 V
• D. +0.32 V

Hint:

$E_{cell} = E_{cathode} - E_{anode}$. A positive $E_{cell}$ indicates a spontaneous reaction.

Answer 1

The Correct Option is D