Step 1: Data provided.
Temperature, \( T = 273 \, {K} \). Molecular mass of oxygen, \( M = 32 \times 10^{-3} \, {kg} \).
Step 2: Speed of sound calculation.
\[ v = \sqrt{\frac{\gamma RT}{M}} = \sqrt{\frac{1.4 \times 8.3 \times 273}{32 \times 10^{-3}}} \approx 315 \, {m/s} \] The speed of sound in oxygen at STP is approximately 315 m/s.
A particle is moving in a straight line. The variation of position $ x $ as a function of time $ t $ is given as:
$ x = t^3 - 6t^2 + 20t + 15 $.
The velocity of the body when its acceleration becomes zero is: