The solution of $\frac{\partial^2 z}{\partial x^2} + z = 0$, satisfying $z(0,y) = e^y$, $\left(\frac{\partial z}{\partial x}\right)_{x=0} = 1$ is $z(x,y) = $}
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You can quickly eliminate incorrect options by directly evaluating the conditions:
- Checking $x=0 \Rightarrow z = e^y$ eliminates options (A) and (B) since they give values of $1$ and $1+e^y$.
- Differentiating remaining choices eliminates option (D) based on the second condition.