Question:medium

The solubility product of AgBr is \(4.9 \times 10^{-13}\) at a certain temperature. Calculate the molar solubility of AgBr.

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For salts of type \(AB\), \[ K_{sp} = s^2 \]
Updated On: May 19, 2026
  • \(4 \times 10^{-6}\ \text{mol dm}^{-3}\)
  • \(4 \times 10^{-7}\ \text{mol dm}^{-3}\)
  • \(7 \times 10^{-7}\ \text{mol dm}^{-3}\)
  • \(3 \times 10^{-8}\ \text{mol dm}^{-3}\)
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The Correct Option is C

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