Step 1: Hydraulic head must have units of length (m or cm), since it is measured in the field as a column height.
Step 2: Check each option's unit: energy/mass gives \( \text{m}^2/\text{s}^2 \); energy/volume gives Pascal (pressure); energy/weight gives \( \text{m} \).
Step 3: Only energy per unit weight reduces to a length unit, matching hydraulic head.
Step 4: The correct option is potential energy per unit weight of soil water.