Question:medium

The slope of the tangent to the curve \( y^2 e^{xy} = 9e^{-3}x^2 \) at \( (-1, 3) \) is:

Show Hint

For terms like \(e^{xy}\), first keep the exponential unchanged and differentiate the exponent separately using product rule.
Updated On: May 6, 2026
  • \( \frac{-15}{2} \)
  • \( \frac{-9}{2} \)
  • \( 15 \)
  • \( \frac{15}{2} \)
  • \( \frac{9}{2} \)
Show Solution

The Correct Option is D

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