Question:medium
The slope of the straight line joining the centre of the circle \( x^2 + y^2 - 8x + 2y = 0 \) and the vertex of the parabola \( y = x^2 - 4x + 10 \) is:
The slope of the straight line joining the centre of the circle \( x^2 + y^2 - 8x + 2y = 0 \) and the vertex of the parabola \( y = x^2 - 4x + 10 \) is:
Show Hint
To find the vertex of \( y = f(x) \) quickly, set \( f'(x) = 0 \). Here, \( y' = 2x - 4 = 0 \Rightarrow x = 2 \).
Updated On: May 6, 2026
- \( \frac{-5}{2} \)
- \( \frac{-7}{2} \)
- \( \frac{-3}{2} \)
- \( \frac{5}{2} \)
- \( \frac{7}{2} \)
Show Solution
The Correct Option is
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