Question:medium

The slope of the normal to the curve $y = 2x^2 + 3\sin x$ at $x = 0$ is:

Show Hint

Remember: $m_{\text{tangent}} \times m_{\text{normal}} = -1$. Once you find the derivative value as $3$, its negative reciprocal is immediately $-\frac{1}{3}$.
Updated On: May 31, 2026
  • $-\frac{1}{3}$
  • $\frac{1}{3}$
  • $-3$
  • $3$
Show Solution

The Correct Option is A

Solution and Explanation

Was this answer helpful?
0

Top Questions on Tangents and Normals

Questions Asked in AP EAPCET exam