Question:medium

The single line diagram of a lossless system is shown in the figure. The system is operating in steady-state at a stable equilibrium point with the power output of the generator being \( P_{max} \sin \delta \), where \( \delta \) is the load angle and the mechanical power input is \( 0.5 P_{max} \). A fault occurs on line 2 such that the power output of the generator is less than \( 0.5 P_{max} \) during the fault. After the fault is cleared by opening line 2, the power output of the generator is \( \frac{P_{max}}{\sqrt{2}} \sin \delta \). If the critical fault clearing angle is \( \pi/2 \) radians, the accelerating area on the power angle curve is _________________ times \( P_{max} \) (rounded off to 2 decimal places).

 

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For fault analysis, integrate the power difference over the fault clearing angle to calculate the accelerating area.
Updated On: Feb 3, 2026
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Correct Answer: 0.12

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