Question

The shortest distance between the lines \[ x = y + 2 = 6z - 6 \] and \[ x + 1 = 2y = -12z \] is:

• A. \( \dfrac{1}{2} \)
• B. \( 2 \)
• C. \( 1 \)
• D. \( \dfrac{3}{2} \)

Hint:

For shortest distance problems involving skew lines: \[ d= \frac{|(\vec{a}_2-\vec{a}_1)\cdot(\vec{b}_1\times\vec{b}_2)|} {|\vec{b}_1\times\vec{b}_2|} \] Always convert symmetric equations carefully before extracting direction ratios.

Answer 1

The Correct Option is B