Question:medium
The shortest distance between the circles \( (x-1)^2 + (y+2)^2 = 1 \) and \( (x+2)^2 + (y-2)^2 = 4 \) is:
The shortest distance between the circles \( (x-1)^2 + (y+2)^2 = 1 \) and \( (x+2)^2 + (y-2)^2 = 4 \) is:
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If \( |C_1C_2| < |r_1 - r_2| \), one circle is inside the other and the shortest distance is \( |r_1 - r_2| - |C_1C_2| \).
Updated On: May 6, 2026
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- \( 2 \)
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The Correct Option is B
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