Question:medium

The second-order correction to the energy of the ground state is always:

Show Hint

A useful physical insight: "The ground state always gets pushed down by second-order perturbations." Because the denominator \((E_0^{(0)} - E_m^{(0)})\) forces every term to be negative, \(E_0^{(2)}\) can never be positive.
Updated On: Jun 25, 2026
  • Zero
  • Imaginary
  • Positive
  • Negative
Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?
0

Top Questions on Quantum Mechanics