Question

The sap of a plant cell has an osmotic potential of -10 bars and there is a wall pressure of 2 bars, when this cell is placed with an osmotic potential of -3 bars, the force causing water to enter the cell is:

• A. -8 bar
• B. -7 bar
• C. -5 bar
• D. -3 bar

Hint:

To quickly find the answer using the DPD method:
- \(\text{DPD of cell} = 10 - 2 = 8 \text{ bars}\).
- \(\text{DPD of solution} = 3 \text{ bars}\).
- \(\text{Net driving force} = 8 - 3 = 5 \text{ bars}\).

Answer 1

The Correct Option is C