To determine the roots of the quadratic equation \(x^2 + 5x + 6 = 0\), we will use the factorization method.
- Compare the equation \(x^2 + 5x + 6 = 0\) with the general quadratic equation \(ax^2 + bx + c = 0\). Here, \(a = 1\), \(b = 5\), and \(c = 6\).
- To factorize the quadratic expression, we need two numbers whose product is \(a \cdot c = 1 \cdot 6 = 6\) and whose sum is \(b = 5\).
- The numbers that satisfy these conditions are \(2\) and \(3\) because:
- Product: \(2 \cdot 3 = 6\)
- Sum: \(2 + 3 = 5\)
- Now, rewrite the middle term \(5x\) as \(2x + 3x\):
- \(x^2 + 5x + 6 = x^2 + 2x + 3x + 6\)
- Factor by grouping:
- Group the first two terms: \(x(x + 2)\)
- Group the last two terms: \(3(x + 2)\)
- Combine these to get: \((x + 2)(x + 3) = 0\)
- Setting each factor to zero gives the roots:
- \(x + 2 = 0 \implies x = -2\)
- \(x + 3 = 0 \implies x = -3\)
The roots of the quadratic equation \(x^2 + 5x + 6 = 0\) are -3 and -2.
Therefore, the correct answer is: -3, -2.