Question:medium

The rms and the average value of an ac voltage \[ V=V_0\sin\omega t \] over a cycle respectively will be:

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For a sinusoidal AC quantity: \[ V_{\text{rms}}=\frac{V_0}{\sqrt2} \] \[ I_{\text{rms}}=\frac{I_0}{\sqrt2} \] and the average value over one complete cycle is always \[ 0. \] Do not confuse this with the average value over only one half-cycle, which is \(\frac{2V_0}{\pi}\).
  • \(\dfrac{V_0}{2},\dfrac{V_0}{2}\)
  • \(\dfrac{V_0}{\pi},\dfrac{V_0}{2}\)
  • \(\dfrac{V_0}{\sqrt{2}},0\)
  • \(V_0,\dfrac{V_0}{2}\)
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The Correct Option is C

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