The resultant capacity between points A and B in the given circuit is
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For infinite or repeating ladder networks, assume the total equivalent capacitance is $X$, and solve for $X$ by setting up an algebraic equation based on the repeating unit. For finite networks, iterative reduction is the most reliable method.
Step 1: Plan the reduction.
The network is a ladder of capacitors. We collapse it step by step using two rules: series gives $\tfrac{C_1 C_2}{C_1+C_2}$ and parallel gives $C_1+C_2$.
Step 2: Combine the far end.
The pair at the far end (each $C$) in series gives $\tfrac{C}{2}$, and joining the branch capacitor in parallel builds it back up.
Step 3: Work toward the terminals.
Repeating series then parallel along the rungs of this particular ladder keeps folding the capacitances inward toward A and B.
Step 4: Read the result.
Carrying the reduction through to the ends, the equivalent capacitance between A and B comes out to $3C$.
\[ \boxed{3C} \]
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