Question

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1000 ohm. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.125 × 10−3 S cm−1?

Answer 1

Cell Constant (K) Calculation

The cell constant \(K\) is determined by the formula:

\[ K = R \cdot \kappa \]

Definitions of variables:

• \(R\) represents resistance, measured in ohms (\(\Omega\)).
• \(\kappa\) denotes conductivity, measured in S/cm.

Provided values:

• \(R = 1000\ \Omega\)
• \(\kappa = 0.125 \times 10^{-3} \text{ S/cm}\)

Upon substitution:

\[ K = 1000 \times 0.125 \times 10^{-3} = 0.125\ \text{cm}^{-1} \]

The calculated cell constant is \(0.125\ \text{cm}^{-1}\).