Question:medium

The relationship between air-base (B), photographic base (b), flying height (H), and focal length of lens (f) for an aerial photograph is given by:

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In photogrammetry, $B$ (air-base) is proportional to $H$ (flying height) and inversely proportional to $f$ (focal length).
Updated On: Feb 18, 2026
  • $B = \dfrac{bH}{f}$
  • $B = \dfrac{f b}{H}$
  • $B = \dfrac{b}{fH}$
  • $B = \dfrac{b}{(H-f)}$
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The Correct Option is A

Solution and Explanation

Step 1: Recall the photogrammetry formula.
The relationship is established from the similarity of triangles in aerial photogrammetry: \[\frac{B}{b} = \frac{H}{f}\]

Step 2: Rearrange the formula.
\[B = \frac{bH}{f}\]

Step 3: Final Answer.
The derived formula is $B = \dfrac{bH}{f}$, thus option (A) is confirmed as correct.

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