When the refractive index of prism material is provided and the angle of minimum deviation equals the prism's angle, the angle of the prism is determined using the prism's angle of deviation formula.
The formula connecting refractive index (\( n \)), prism angle (\( A \)), and minimum deviation angle (\( \delta_m \)) is:
\(n = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}\)
Given values:
Substituting \( \delta_m = A \) into the formula yields:
\(n = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
With \( n = 3 \), the equation becomes:
\(3 = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)}\)
The objective is to find the angle \( A \) that satisfies this equation.
Solving this equation through trigonometric identities and known values reveals:
\(A = 60^\circ\)
This result aligns with the given options, confirming the prism angle is 60°.
Consequently, the correct answer is 60°.
An object AB is placed 15 cm on the left of a convex lens P of focal length 10 cm. Another convex lens Q is now placed 15 cm right of lens P. If the focal length of lens Q is 15 cm, the final image is _____
