Question:medium

The reagent(s) used in hydroboration oxidation of propene are:
(A) B\(_2\)H\(_6\)
(B) H\(_2\)O
(C) H\(_2\)O\(_2\)
(D) OH\(^-\)

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Hydroboration-oxidation is a useful reaction for the anti-Markovnikov addition of water to alkenes. The reaction proceeds with syn addition to form an alcohol.
Updated On: Mar 27, 2026
  • (A), (B) and (D) only
  • (A), (B) and (C) only
  • (A), (B), (C) and (D)
  • (B), (C) and (D) only
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding Hydroboration Oxidation.
Hydroboration-oxidation of alkenes is a two-step process. The first step involves the reaction of the alkene with diborane (B\(_2\)H\(_6\)). The second step is an oxidation reaction employing hydrogen peroxide (H\(_2\)O\(_2\)) to produce alcohols.
Step 2: Reagents Used.
- (A) B\(_2\)H\(_6\) (diborane): This reagent is central to the hydroboration step, reacting with the alkene to form an organoborane intermediate.
- (B) H\(_2\)O (water): Water is crucial for the oxidation step, reacting with the intermediate to yield an alcohol.
- (C) H\(_2\)O\(_2\) (hydrogen peroxide): Hydrogen peroxide facilitates the oxidation of the organoborane intermediate to an alcohol.
- (D) OH\(^-\) (hydroxide ion): The hydroxide ion is not a reactant in this process.
Step 3: Conclusion.
For the hydroboration oxidation of propene, the necessary reagents are B\(_2\)H\(_6\), H\(_2\)O, and H\(_2\)O\(_2\). Therefore, the correct selection is:
(2) (A), (B), and (C) only.
Final Answer: \[\boxed{\text{The correct answer is (A), (B) and (C) only.}}\]
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