The reaction quotient \(Q\) is used to determine the direction in which a chemical reaction will proceed to reach equilibrium. It is given by the expression:
\(Q = \frac { [NH_3]^2}{[N_2][H_2]^3}\)
Here, \(Q\) is compared with the equilibrium constant \(K_C\) to predict the reaction's direction:
If \(Q = K_C\), the system is at equilibrium, and no net change occurs.
If \(Q < K_C\), the reaction will proceed from left to right, favoring the formation of products to reach equilibrium.
If \(Q > K_C\), the reaction will proceed from right to left, favoring the formation of reactants to reach equilibrium.
Given the options and based on the aforementioned reasoning:
Consequently, the correct answer is the reaction will proceed from right to left if \(Q > K_C\).
An ideal massless spring \( S \) can be compressed \( 1 \) m by a force of \( 100 \) N in equilibrium. The same spring is placed at the bottom of a frictionless inclined plane inclined at \( 30^\circ \) to the horizontal. A \( 10 \) kg block \( M \) is released from rest at the top of the incline and is brought to rest momentarily after compressing the spring by \( 2 \) m. If \( g = 10 \) m/s\( ^2 \), what is the speed of the mass just before it touches the spring?
